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Solving Probability Questions on the SAT

These Digital SAT questions give you a probability scenario or two-way table and ask you to find a simple probability, a conditional probability, or the probability of two events together.

Problem-Solving and Data Analysis · Updated August 3, 2026 · 8 min read
01

The method: Table → Favorable → Divide

Every SAT probability question reduces to the same fraction: P(event) = favorable outcomes / total outcomes. A bag of 20 marbles with 8 red ones gives P(red) = 8/20 = 2/5. The only extra work on most SAT questions is figuring out which numbers count as “favorable” and which count as “total” — and a two-way table organizes exactly those counts for you.

A survey of 250 students recorded whether each plays a sport and whether each plays an instrument:

Plays instrumentNo instrumentTotal
Plays a sport6090150
No sport5050100
Total110140250

Row and column totals are already favorable/total pairs waiting to be divided. Walk through pulling a conditional probability out of this table below.

Read a two-way table
Step 1 · Total
150 play a sport

The row total for “Plays a sport” — this becomes the denominator for anything conditioned on playing a sport.

Try it

Using the table above, what is P(plays a sport)?

02

Two-way tables and reading the right cell

A two-way table has three kinds of numbers: row totals and column totals (each the total for one category, ignoring the other), single cells (the count for both categories together), and the grand total (everyone). Before dividing anything, decide which of these four numbers the question is actually asking for.

Row total, column total, or single cell?
1 / 3

Using the table above, what value answers each question?

“How many students play a sport?”
Try it

Using the table above, what is P(no sport)?

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03

Conditional probability: P(A | B)

P(A | B) means “the probability of A, given that B already happened.” In a two-way table, that means you divide the joint cell by the row or column total for B — never by the grand total. Restrict your attention to just B's row (or column) first, then find A's share of it.

The order matters: P(instrument | sport) and P(sport | instrument) use the same joint cell but different denominators, and they are generally not equal.

Try it

Using the table above, what is P(plays an instrument | no sport)?

04

Compound events: and / or

For two independent events (a coin flip and a die roll — neither affects the other), multiply: P(A and B) = P(A) × P(B). For mutually exclusive “or” events (a single die roll can't show both a 2 and a 5), add: P(A or B) = P(A) + P(B). If the events can overlap, subtract the overlap once: P(A or B) = P(A) + P(B) − P(A and B).

The most common error is using the wrong operation — adding independent events instead of multiplying them, or forgetting to subtract the overlap for “or” events that can happen together.

Try it

A fair coin is flipped and a fair six-sided die is rolled. What is P(the coin shows heads and the die shows a 5)?

05

Practice until it's automatic

These mix simple probability, table reading, conditional probability, and compound events — the full toolkit for SAT probability questions.

A jar has 9 red and 6 blue marbles. What is P(red)?

Using the table above, what is P(plays a sport and does not play an instrument)?

Using the table above, what is P(plays a sport and plays an instrument)?

Using the table above, what is P(plays an instrument | plays a sport)?

Two independent events have P(A) = 1/4 and P(B) = 2/5. What is P(A and B)?

Rolling a fair die once, what is P(rolling a 2 or a 5)?

Once table-reading and conditional probability feel automatic, the same “restrict, then divide” instinct applies directly to sample-to-population estimates, where you scale a sample proportion up to a full population.

06

Practice questions

Here are five practice problems that help you hone your skills. Use the same method we learned earlier above to solve these problems. Remember, practice makes perfect.

Questions 1–3 use this table: a survey of 300 shoppers found that of the 180 who bought a jacket, 117 also bought gloves and 63 did not. Of the 120 who did not buy a jacket, 21 bought gloves and 99 did not.

Practice 1

What is P(bought a jacket)?

Practice 2

What is P(bought gloves | bought a jacket)?

Practice 3

What is P(did not buy a jacket and did not buy gloves)?

Practice 4

Two independent events have P(A) = 3/8 and P(B) = 2/3. What is P(A and B)?

Practice 5

A fair spinner has 8 equal sections numbered 1 through 8. What is P(landing on a multiple of 3 or a multiple of 4)?

Next up
Keep going in SAT Math.

Data inference and evaluating statistical claims build on the same table-reading skills.

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