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SHSAT: Inequalities with whole-number answers

Solve linear inequalities, turn the solution into the greatest or least integer the situation allows, and count the integers in a range.

Updated October 3, 2026

When an inequality gives a decimal answer but the question needs a whole number, how do you know which integer to choose?

Short answer

Solve the inequality, flipping the sign if you divide by a negative. Then round down for a limit, round up to reach a goal, and test the boundary in the words.

Know first: Solving two-step equations, Integers on a number line

Step 1 of 5

Solve like an equation, then pick the integer the story allows

An inequality is solved the same way as an equation, with one extra rule: if you multiply or divide both sides by a negative number, flip the inequality sign.

The solution is usually a range such as x < 10.9. When the answer has to be a whole number of kits, tickets or rounds, the context decides whether you round down or round up.

From the words to the integer
WordsSymbolIf you get 10.9, answerIf you get exactly 11, answer
at most, no more than≤greatest integer: 1011
fewer than, strictly less than<greatest integer: 1010
at least, no fewer than≥least integer: 1111
more than, greater than>least integer: 1112

Strict signs exclude the boundary itself. Check the boundary number in the words.

Step 2 of 5

Find the budget first, then divide

Worked example: Jerseys on a budget

A team has $200 and must keep $25 for snacks. Jerseys cost $16 each. What is the greatest number of jerseys the team can buy?

  1. A10
  2. B11
  3. C12
  4. D13
  1. 1

    Find the spending money

    200 − 25 = $175 can be spent.

  2. 2

    Write the inequality

    16j ≤ 175, so j ≤ 175/16, which is between 10 and 11.

  3. 3

    Choose the integer

    Only whole jerseys count, and spending can't pass $175, so round down: 10. Check: 10 jerseys cost $160; 11 cost $176, which is too much.

  4. 4

    See why the other choices are there

    11 rounds up past the budget. 12 ignores the $25 reserve. 13 ignores the reserve and also rounds up.

Answer

10 jerseys

Find the wrong step

Find the smallest integer x for which 7 − 3x < −11.

  1. 1

    Subtract 7 from both sides: −3x < −18.

  2. 2

    Divide both sides by −3: x < 6.

    What went wrong

    Dividing by a negative number flips the sign. The result should be x > 6.

  3. 3

    The integer just below 6 is 5, so the answer is 5.

The fix

x > 6, so the smallest integer is 7. Check: 7 − 21 = −14, and −14 < −11. With x = 5, 7 − 15 = −8, which is not less than −11.

Rounding up and counting

Round up for "at least": with 35 points and 6 points per round, reaching at least 100 needs 6r ≥ 65, so r ≥ 10 5/6. Answer: 11 rounds.
Count integers carefully: −4 ≤ n < 3 includes −4 but not 3, so n = −4, −3, −2, −1, 0, 1, 2. That's 7 integers.

Step 3 of 5

Check the boundary every time

Check yourself · Question 1

How many integers n satisfy −4 < n ≤ 5?

A1
B8
C9
D10

Answer: C

−4 is excluded and 5 is included, so n = −3, −2, −1, 0, 1, 2, 3, 4, 5. That's 9 integers.

Check yourself · Question 2

A phone plan charges a $14 monthly fee plus $3 per gigabyte. What is the greatest whole number of gigabytes that keeps the bill strictly less than $50?

A11
B12
C16
D21

Answer: A

3g + 14 < 50 gives 3g < 36, so g < 12. The greatest integer below 12 is 11. Check: 11 gigabytes cost $47; 12 cost exactly $50, which is not less than $50.

Trap answer: 12

Keeping the boundary

Why it looks right
Solving 3g = 36 gives exactly 12, and a clean answer feels finished.
Why it's wrong
Strictly less than $50 rules out a bill of exactly $50. The boundary value fails.
The right answer
11, the greatest integer with a bill below $50.

Check yourself · Question 3

An integer n satisfies both 3n − 4 > 8 and 2n + 5 ≤ 23. What is the sum of all possible values of n?

A9
B26
C35
D39

Answer: C

The first gives 3n > 12, so n > 4. The second gives 2n ≤ 18, so n ≤ 9. The integers are 5, 6, 7, 8, 9, and their sum is 35.

Common mistake

I round to the nearest whole number.

Why it's tempting
Rounding to the nearest is the rule you use most often in other classes.
Do this instead
Let the context decide. A budget or capacity limit means round down; reaching a goal means round up. Then test the integer in the words.

Step 4 of 5

What to remember

Remember

  1. Solve as you would an equation, but flip the sign when you multiply or divide by a negative.
  2. Round down for limits such as budgets and capacity, and round up to reach a goal.
  3. Check the boundary: strict signs exclude it, and both conditions must hold at once.

Step 5 of 5

Practice on a real question

Use what you just learned on this question, then check the explanation.

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In your own words

In the practice question, what amount was available to spend, and why did you round in the direction you did?

All sample lessons

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