PERT math formulas and algebra rules.
These 40 rules cover the PERT Mathematics topics, from signed numbers to the quadratic formula. Each comes with a short worked example and a link to the free lesson that teaches it.
How to use this sheet
On PERT Mathematics you can’t bring your own calculator unless an approved disability accommodation allows one, and an on-screen calculator appears only on some questions, so these rules need to be automatic. Use the sheet in three passes:
- Cover the middle column. Read the rule’s name and say how it works, then check yourself.
- Rework the mini example on paper without looking at the answer. If you get stuck, open the lesson: each one explains the rule with several worked examples and a practice question.
- Drill what you missed with the flashcards, then try the rule in practice with the algebra and mathematical models guide or the expressions, polynomials and factoring guide.
The groups follow the order of the free PERT course, so the sheet also works as a checklist for PERT Math: if every example here is easy, your time is better spent on mixed practice.
Arithmetic, fractions and percents
| Rule | How it works | Mini example | Lesson |
|---|---|---|---|
| Order of operations | Grouping and exponents first, then multiplication and division left to right, then addition and subtraction left to right | −4 + 3(2 − 7) = −4 + 3(−5) = −19 | Signed numbers and order of operations |
| Negative base | An exponent applies only to what it touches; parentheses put the sign under the exponent | −3² = −9, but (−3)² = 9 | Signed numbers and order of operations |
| Signed numbers | Subtracting is adding the opposite; same signs multiply or divide to a positive, different signs to a negative | 5 − (−2) = 7; (−6)(−2) = 12; −12 ÷ 3 = −4 | Signed numbers and order of operations |
| Adding fractions | Rewrite over a common denominator, then add the numerators | 1/4 + 2/3 = 3/12 + 8/12 = 11/12 | Fractions and rational arithmetic |
| Dividing fractions | Multiply by the reciprocal of the nonzero divisor | (3/4) ÷ (2/5) = (3/4)(5/2) = 15/8 | Fractions and rational arithmetic |
| Percent of a quantity | Write the percent as a decimal and multiply; a discount leaves 100% minus the discount | 25% off $72: 0.75 × 72 = $54 | Percents and proportional models |
| Percent change | Divide the change by the original amount, then multiply by 100 | 80 to 92: 12 ÷ 80 = 0.15 = 15% | Percents and proportional models |
| Successive percents | Each percent applies to the amount after the previous change | 100 up 20% is 120; 120 down 20% is 96, a 4% net drop | Percents and proportional models |
| Proportion | Two equal ratios; cross-multiply and solve | x/6 = 10/15, so 15x = 60 and x = 4 | Percents and proportional models |
Exponents and expressions
| Rule | How it works | Mini example | Lesson |
|---|---|---|---|
| Product and quotient of powers | Same base: multiply by adding exponents, divide by subtracting them (base not 0) | x²·x³ = x⁵; x⁵/x² = x³ | Powers and exponent structure |
| Power of a power or product | Multiply exponents; a power of a product applies to every factor | (x²)³ = x⁶; (2x)³ = 8x³ | Powers and exponent structure |
| Zero and negative exponents | a⁰ = 1 and a⁻ⁿ = 1/aⁿ for any nonzero a | 7⁰ = 1; 2⁻³ = 1/8 | Powers and exponent structure |
| Monomial products and quotients | Multiply or divide the coefficients, then apply the exponent rules to each variable | (3x²y)(4xy³) = 12x³y⁴; 12x⁵/(4x²) = 3x³ | Products and quotients of monomials |
| Substitution | Replace each variable with its value inside parentheses, then follow the order of operations | If x = −2: x² − 3x = (−2)² − 3(−2) = 4 + 6 = 10 | Substituting into algebraic expressions |
| Distributive property | a(b + c) = ab + ac; a minus sign before a group changes the sign of every term inside | 2(x − 3) − (x + 4) = 2x − 6 − x − 4 = x − 10 | Distribution and like terms |
| Like terms | Combine only terms with the same variables raised to the same powers | 4x + 3y − x + 2y = 3x + 5y; x² + x stays as it is | Distribution and like terms |
Equations and inequalities
| Rule | How it works | Mini example | Lesson |
|---|---|---|---|
| Linear equation | Do the same operation to both sides, then substitute to check | 3x + 4 = 19, so 3x = 15 and x = 5; check 3(5) + 4 = 19 | Multistep linear equations |
| Fractions and decimals | Multiply every term by the common denominator (or a power of 10) to clear them | x/3 + 1/2 = 5/6; times 6: 2x + 3 = 5, so x = 1 | Linear equations with fractions and decimals |
| Identity or no solution | If the variable cancels, a true statement means every real number works; a false one means none does | 3(x + 2) = 3x + 6: all real numbers. 2(x − 4) = 2x + 1: no solution | Identities, contradictions and parameters |
| Literal equation | Isolate the requested variable with the same steps; note any divisor that cannot be 0 | A = bh/2 gives h = 2A/b, for b ≠ 0 | Solving literal equations |
| Inequality sign flip | Multiplying or dividing both sides by a negative number reverses the inequality | −2x < 6, so x > −3 | Linear inequalities |
| Compound inequalities | “And”: apply each step to all three parts. “Or”: solve each part; the answer is everything that satisfies either | −1 < 2x + 3 ≤ 9 gives −4 < 2x ≤ 6, so −2 < x ≤ 3 | Compound inequalities |
| Linear model | Total = starting amount + rate × units; the rate is the slope | $25 plus $0.40 a mile: C = 25 + 0.40m; 100 miles costs $65 | Building and comparing linear models |
Lines and systems
| Rule | How it works | Mini example | Lesson |
|---|---|---|---|
| Slope | m = (y₂ − y₁)/(x₂ − x₁), rise over run | (1, 2) and (4, 8): m = 6/3 = 2 | Slope and coordinate relationships |
| Slope-intercept form | y = mx + b, where m is the slope and b the y-intercept | y = 2x + b through (1, 2): 2 = 2 + b, so b = 0 | Equations of lines |
| Point-slope form | y − y₁ = m(x − x₁) for slope m through (x₁, y₁) | Slope 3 through (2, 5): y − 5 = 3(x − 2), so y = 3x − 1 | Equations of lines |
| Horizontal and vertical lines | y = c is horizontal with slope 0; x = c is vertical with undefined slope | y = −2 is horizontal; x = −2 is vertical | Equations of lines |
| Parallel and perpendicular | Parallel lines share a slope; perpendicular slopes are negative reciprocals (product −1) | Parallel to y = −4x + 9: slope −4. Perpendicular to y = (2/3)x − 5: slope −3/2 | Parallel and perpendicular lines |
| Solving a system | The solution satisfies both equations; substitute or add equations to eliminate a variable | x + y = 7 and x − y = 1: adding gives 2x = 8, so (4, 3) | Solving simultaneous linear equations |
| Number of solutions | Different slopes: one solution. Same slope, different intercepts: none. Same line: infinitely many | y = 2x + 1 and y = 2x − 3 are parallel: no solution | Interpreting and modeling systems |
Polynomials, quadratics and rational expressions
| Rule | How it works | Mini example | Lesson |
|---|---|---|---|
| Adding and subtracting polynomials | Combine like terms; when subtracting, change the sign of every term in the second polynomial | (3x² + 2x − 5) − (x² − 4x + 1) = 2x² + 6x − 6 | Adding and subtracting polynomials |
| Multiplying binomials | Multiply every term by every term, then combine like terms | (x + 2)(x − 3) = x² − 3x + 2x − 6 = x² − x − 6 | Multiplying binomials |
| Factoring | Take out the greatest common factor first; for x² + bx + c, find two numbers that multiply to c and add to b | 6x² + 9x = 3x(2x + 3); x² + 7x + 12 = (x + 3)(x + 4) | Factoring polynomials |
| Difference of squares | a² − b² = (a − b)(a + b) | x² − 9 = (x − 3)(x + 3) | Factoring polynomials |
| Polynomial division | Divide leading terms step by step; check that quotient × divisor + remainder gives the original | (2x² + 5x − 3) ÷ (x + 3) = 2x − 1, since (2x − 1)(x + 3) = 2x² + 5x − 3 | Dividing polynomials |
| Zero-product property | Move every term to one side, factor, then set each factor equal to 0 | x² − 7x + 10 = 0: (x − 2)(x − 5) = 0, so x = 2 or 5 | Solving quadratic equations |
| Square roots of both signs | If a square equals a positive number, use the positive and negative roots | (x − 3)² = 16: x − 3 = 4 or −4, so x = 7 or −1 | Solving quadratic equations |
| Quadratic formula | For ax² + bx + c = 0, x = (−b ± √(b² − 4ac)) / (2a) | 2x² + 3x − 2 = 0: x = (−3 ± √25)/4, so x = 1/2 or −2 | Solving quadratic equations |
| Rational domain | Exclude every value that makes an original denominator 0, even after canceling | (x² − 9)/(x + 3) = x − 3, with x ≠ −3 | Rational expressions, equations and domains |
| Checking rational equations | Clear denominators, solve, then reject any answer that is excluded | x/(x − 2) = 2/(x − 2) gives x = 2, which is excluded: no solution | Rational expressions, equations and domains |
Flashcards
Fifteen core rules as flashcards. Say the rule out loud before you flip the card, and note any you hesitate on so you can rework their examples above.
1 of 15 · Select the card to reveal the meaning and example.
Put the rules into practice
Knowing a rule and using it under test conditions are different skills. After a pass through the sheet, build a 10-question Math set in the question bank and, for every miss, find the row above that would have prevented it. When the sheet feels easy, take the Mathematics practice test, or follow the PERT study plan to fit the rules into a schedule.
Frequently asked questions
Sources
PERT rules are set by Florida law and by each college. These are the pages this guide relies on; your testing center’s current instructions take priority.
- Florida Department of Education, P.E.R.T. Student Study Guide (undated, linked from the FDOE page). Accessed October 3, 2026.
- Florida Department of Education, Demonstration of College Readiness (Formerly Common Placement Testing/PERT). Accessed October 3, 2026.