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AP Physics 1: Algebra-Based · Framework 2026-27
Unit 8

Fluids

Fluid behavior follows from density, pressure forces, Newton’s laws, and conservation of mass and energy under clearly stated static or ideal-flow conditions.

Exam weight
10–15%
Topics
4

Introduction

Fluid behavior follows from density, pressure forces, Newton’s laws, and conservation of mass and energy under clearly stated static or ideal-flow conditions.

Begin every fluid problem by deciding whether the fluid is static or flowing and whether the ideal-fluid assumptions are justified. Density describes mass per volume; pressure describes perpendicular force per area. A pressure difference, not pressure alone, determines the net force on a surface.

Hydrostatics explains depth-dependent pressure and buoyancy. Steady ideal flow adds continuity and Bernoulli relations. Those equations assume conditions such as uniform density, negligible viscosity, a filled flow path, and no unaccounted pump or dissipative transfer.

01
Microscopic state and density

fluid model

02
Pressure gradient

hydrostatic force

03
Pressure-force imbalance

buoyancy

04
Mass and energy conservation

ideal flow

Current exam guidance: Aligned to the current 2026–27 AP Physics 1 framework, with algebra-based modeling, experimental reasoning, and explicit assumptions.
8.1

Internal Structure and Density

How do particle organization and mass per volume distinguish fluid models?

Short answer

Liquids and gases flow because they lack a fixed shape, while density quantifies mass per volume and the ideal-fluid model suppresses compression and viscosity.

Know firstMass and volume · Ratios and graph slope · Particle models

Move from particle behavior to a measurable ratio

Solids resist changes of shape because their particles remain organized around relatively fixed positions. Liquids preserve approximately fixed volume while rearranging to take the container’s shape. Gases rearrange and commonly change volume. Liquids and gases are therefore fluids: they can flow and do not retain a fixed shape under ordinary shear stress.

Density is ρ=m/V\rho=m/V. For a uniform sample, cutting the sample changes its mass and volume in the same proportion, so density remains unchanged. A mass-versus-volume graph for one homogeneous material has slope ρ\rho. If a sample is nonuniform, total mass divided by total volume is an average density; it does not describe the density at every point.

An ideal fluid is incompressible and nonviscous. Incompressible means a moving element does not appreciably change density. Nonviscous means the model neglects internal friction and energy dissipation from shear. Real water can often be approximated as incompressible, but every real fluid has some viscosity. The model is useful only when those omitted effects are small enough for the claim being made.

Physics model

Density compares mass with occupied volume

Change sample volume at fixed density and compare the proportional change in mass.

Volume
4 L
Mass
4.8 kg
Density
1.2 kg/L
sample containermass-carrying particlesvolume bracket
Density compares mass with occupied volumeChange sample volume at fixed density and compare the proportional change in mass. The table below states the model assumptions and relationships without relying on color or motion.volume
ρ=mV\rho=\frac{m}{V}
Read this figure without the graphic

Change sample volume at fixed density and compare the proportional change in mass. The table below states the model assumptions and relationships without relying on color or motion.

QuantityMeaning
Density1.2 kg/L
MassρV\rho V
Intensive propertyDensity does not depend on sample amount in a uniform material

Read density as a graph slope

  1. Measure mass and volume for several portions.
  2. Plot mass vertically against volume horizontally.
  3. Use the best-fit slope; inspect whether an intercept is consistent with zero.
Result
ρ=mV=ΔmΔV\rho=\frac{m}{V}=\frac{\Delta m}{\Delta V}
Units: ρ\rho in kg/m3^3, mm in kg, and VV in m3^3

Boundary cases

  • V=0V=0 is not a valid sample ratio.
  • A curved mass–volume relation signals nonuniform composition or measurement/model trouble.

For a uniform material, mass increases linearly with volume and the line’s slope is density.

Evaluate a density claim

  1. Identify the material and whether it is uniform.
  2. Use consistent mass and volume units.
  3. Compute or infer the mass–volume slope.
  4. Separate the density ratio from total mass and state whether it is local or average.

Keep these three ideas

  • Liquids and gases are fluids because they lack fixed shape.
  • Uniform-sample density is an intensive mass-to-volume ratio.
  • Ideal-fluid claims explicitly neglect compression and viscosity.

Keep reading Unit 8: Fluids

You just read the first topic free. Your free trial opens the rest of this unit, every AP Physics 1 unit, and all 19 AP courses.

  • 8.1 Internal Structure and DensityRead
  • 8.2 Pressure
  • 8.3 Fluids and Newton’s Laws
  • 8.4 Fluids and Conservation Laws
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