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ASVAB percentage practice

A percentage describes a comparison with a particular whole. Identify that whole before multiplying or dividing: most difficult percentage problems change the base somewhere in the story.

Test Ninjas Research · Updated September 29, 2026

What you will practice

  • Identify the amount that represents 100%.
  • Choose multiplication or division from the unknown.
  • Check discounts and changes against the original value.

Suggested pace: 10 minutes on examples · 10–15 minutes on questions · 5 minutes on review. Take a second session if a method needs more work.

Keep in mind: part = decimal rate × whole

Method 1 of 4

Find the percentage of a quantity

Translate “percent” as “out of 100.” You can use a decimal, a fraction, or a familiar benchmark. Choose the form that makes the arithmetic easiest, then check whether you were asked for the amount of a change or the final amount.

  1. Name the original whole and the percentage.
  2. Convert the percentage to a decimal or fraction.
  3. Multiply to find the part; add or subtract it only if the question asks for a new total.

Worked example

A $64 tool kit is discounted by 25%. What is the sale price before tax?

  1. 25% = 25/100 = 1/4.
  2. The discount is $64 ÷ 4 = $16.
  3. The sale price is $64 − $16 = $48.

Answer: $48

Check it: A quarter off leaves three quarters of the original price. Three quarters of $64 is $48.

Now try it without looking back

A $40 item is 25% off. What is the sale price?

Check your reasoning

$30. The discount is one quarter of $40, or $10; subtract it from the original price.

Common mistake: Stopping at $16 answers “How much is saved?” Read the last sentence again before choosing an answer.

Method 2 of 4

Work backward to the original whole

When a final amount and its percentage are known, the unknown is the whole. Dividing by the decimal rate reverses multiplication. A price after a 20% discount is 80% of its original value, so use 0.80 rather than 0.20.

  1. Write what percentage the known amount represents.
  2. Use whole = part ÷ decimal rate.
  3. Substitute the result back into the original situation.

Worked example

A jacket costs $72 after a 20% discount. What was its original price?

  1. The buyer pays 100% − 20% = 80% of the original price.
  2. 0.80 × original price = 72.
  3. Original price = 72 ÷ 0.80 = $90.

Answer: $90

Check it: 20% of $90 is $18. Subtracting $18 gives the stated $72 sale price.

Now try it without looking back

A sale price of $48 is 80% of the original. What was the original price?

Check your reasoning

$60, because 48 ÷ 0.80 = 60. Check: 80% of $60 is $48.

Common mistake: Adding 20% of $72 gives $86.40. That uses the sale price as the base, but the discount was taken from the original price.

Method 3 of 4

Measure a change using the starting value

Percentage change compares the amount gained or lost with the starting amount. The subtraction finds the change; the division tells you how large it is relative to the original. If two rates themselves change, distinguish percentage points from relative percentage change.

  1. Find the difference between the new and original values.
  2. Divide the difference by the original value.
  3. Multiply by 100 and label the result as an increase or a decrease.

Worked example

Weekly production rises from 80 units to 100 units. By what percentage does production increase?

  1. Increase = 100 − 80 = 20 units.
  2. Increase ÷ original = 20/80 = 1/4.
  3. 1/4 × 100% = 25%.

Answer: 25% increase

Check it: A 25% increase from 80 adds 20. Dividing by 100 instead would measure the increase against the ending value.

Now try it without looking back

A quantity falls from 50 to 40. What is the percentage decrease?

Check your reasoning

20%. The decrease is 10, and the starting value is 50: 10/50 × 100% = 20%.

Common mistake: A pass rate moving from 60% to 75% increases by 15 percentage points, but its relative increase is 15/60 = 25%. Those are different questions.

Method 4 of 4

Apply successive changes one at a time

After the first change, the whole for the second change is different. Multipliers keep track of that: an increase of 10% multiplies by 1.10, while a decrease of 10% multiplies by 0.90. Opposite percentage changes therefore do not usually cancel.

  1. Convert each change to a multiplier.
  2. Apply the multipliers in the order described.
  3. Compare the final quantity with the original if a net change is requested.

Worked example

A $200 item increases in price by 10%, then receives a 10% discount. What is the final price?

  1. After the increase: $200 × 1.10 = $220.
  2. After the discount: $220 × 0.90 = $198.
  3. The final price is $2 below the original.

Answer: $198

Check it: The increase was $20, but the later discount was $22 because it used a larger base.

Now try it without looking back

A $100 price rises by 20%, then falls by 20%. Where does it finish?

Check your reasoning

$96: 100 × 1.20 × 0.80. The $24 decrease is larger than the $20 increase.

Common mistake: Adding +10% and −10% assumes both percentages refer to the same starting amount.

Practice percentages

Before each practice question, underline the amount that represents 100%. If the problem changes the group or price, write a new base for the next step.

Work the first six questions with the explanations closed. Review any missed or guessed answers before continuing with the other six. If you cannot set up a problem, return to its method above and try again from a blank page.

Percentages: 12 practice questions

Work through one question at a time. Explain your approach, check the worked answer, then move on. Use scratch paper for calculations.

0 of 12 checked · 0 correct.

Progress is saved in this browser. These original study questions do not produce an official AFQT score.

Question 1: Reverse a percentage complement

Question 1 · Reverse a percentage complement · easy

A display holds only blue-capped and red-capped bottles. Blue-capped bottles make up 40% of the display, and there are 18 red-capped bottles. How many bottles are in the display altogether?

Choose an answer for question 1
Worked answer and explanation

Answer: C. 30

Red-capped bottles make up the remaining 60%. If 60% of the total is 18, the total is 18 ÷ 0.60 = 30. Dividing by 40% gives 45, but 18 counts the red group, not the blue group. Twelve is the number with blue caps.

Question 2: Undoing two price changes

Question 2 · Undoing two price changes · medium

A service’s original price is increased by 25%. A separate $6 fee is then added, making the final charge $56. What was the original price?

Choose an answer for question 2
Worked answer and explanation

Answer: A. $40

Undo the last change first: $56 − $6 = $50. That $50 is 125% of the original price, so the original is $50 ÷ 1.25 = $40. Subtracting 25% from $56 uses the wrong base and fails to remove the separate fee correctly.

Question 3: Percentage within a subgroup

Question 3 · Percentage within a subgroup · medium

Of 80 forms, 60% are checked manually and the rest are checked automatically. One quarter of the manually checked forms contain errors. None of the automatically checked forms contain errors. How many forms contain errors?

Choose an answer for question 3
Worked answer and explanation

Answer: A. 12

There are 80 × 0.60 = 48 manually checked forms. One quarter of that group is 48 ÷ 4 = 12. The 20 choice applies one quarter to all 80 forms, but the error fraction applies only to the manual subgroup.

Question 4: Percentage points and relative change

Question 4 · Percentage points and relative change · hard

A process loses a certain percentage of its input material. A redesign lowers that loss rate by 6 percentage points. This change is a 30% reduction in the old loss rate. What is the new loss rate?

Choose an answer for question 4
Worked answer and explanation

Answer: D. 14%

The 6-percentage-point decrease is 30% of the old rate, so the old rate was 6 ÷ 0.30 = 20%. Subtracting 6 percentage points gives a new rate of 14%. Applying 70% to 6 to obtain 4.2 uses the decrease as though it were the old rate; 1.8 likewise applies 30% to the wrong base.

Question 5: Combining containers at the same filling percentage

Question 5 · Combining containers at the same filling percentage · easy

Three containers of different capacities are each 40% full of the same liquid. All their liquid is poured into one empty container whose capacity equals the sum of the three original capacities. No liquid is lost. What percentage full is the new container?

Choose an answer for question 5
Worked answer and explanation

Answer: B. 40%

If the original capacities are a, b and c, the liquid totals 0.40a + 0.40b + 0.40c = 0.40(a + b + c). The new capacity is a + b + c, so it is still 40% full. Adding the three percentages to get 120% ignores that the total capacity also combines all three containers.

Question 6: Percentages of unequal totals

Question 6 · Percentages of unequal totals · medium

Garden A starts with 150 seedlings, of which 80% survive. Garden B starts with 100 seedlings, of which 90% survive. How many more seedlings survive in Garden A than in Garden B?

Choose an answer for question 6
Worked answer and explanation

Answer: D. 30

Garden A has 150 × 0.80 = 120 survivors, and Garden B has 100 × 0.90 = 90. The difference is 30 seedlings. A lower percentage can still produce more survivors with a larger starting group. Applying the 10-percentage-point difference to the combined 250 seedlings gives 25, but the percentages refer to separate groups.

Question 7: Conditional percentage within a category

Question 7 · Conditional percentage within a category · medium

In a sports-equipment shipment, 40% of all items are helmets. Junior-size helmets make up 18% of all items in the shipment. What percentage of the helmets are junior-size?

Choose an answer for question 7
Worked answer and explanation

Answer: D. 45%

Use helmets, rather than the entire shipment, as the denominator: 18/40 = 0.45, or 45%. For every 100 items, there are 40 helmets and 18 junior helmets. Multiplying 18% by 40% gives 7.2% but does not answer the within-helmet question.

Question 8: Changing a percentage numerator and base

Question 8 · Changing a percentage numerator and base · hard

One week a workshop produces 800 parts. The next week it produces 25% more parts while making 20% fewer defective parts than the first week. Defective parts are 4% of the second week’s production. What percentage of the first week’s parts were defective?

Choose an answer for question 8
Worked answer and explanation

Answer: D. 6.25%

Second-week production is 800 × 1.25 = 1,000 parts, with 1,000 × 0.04 = 40 defective. Forty is 80% of the earlier defective count, so that count was 40 ÷ 0.80 = 50. The first-week rate is 50 ÷ 800 × 100% = 6.25%. Five percent uses the later defective count with the earlier production total.

Question 9: The additional capacity from a percentage increase

Question 9 · The additional capacity from a percentage increase · easy

A bottle holds 500 milliliters. Its replacement has a capacity 20% greater than that amount. How many additional milliliters can the replacement hold?

Choose an answer for question 9
Worked answer and explanation

Answer: B. 100 milliliters

The added capacity is 20% of 500 milliliters: 0.20 × 500 = 100 milliliters. The replacement’s total capacity is 600 milliliters, but the question asks only for the additional amount. The percentage number 20 is not itself a volume.

Question 10: Production rate versus time per item

Question 10 · Production rate versus time per item · medium

A machine originally takes 32 minutes to make one part. After an adjustment it takes 24 minutes per part. Running continuously at each constant rate, by what percent does its hourly production rate increase?

Choose an answer for question 10
Worked answer and explanation

Answer: C. 33 1/3%

Hourly output changes from 60/32 to 60/24 parts. The rate ratio is (60/24)/(60/32) = 32/24 = 4/3, an increase of 1/3 or 33 1/3%. Twenty-five percent is the decrease in time per part, 8/32, but output is the reciprocal of time per part.

Question 11: Overall percentage from unequal groups

Question 11 · Overall percentage from unequal groups · medium

A batch of 50 forms has a 40% error rate. Another batch of 150 forms has a 10% error rate. What percentage of the combined 200 forms contain errors?

Choose an answer for question 11
Worked answer and explanation

Answer: A. 17.5%

The groups contain 50 × 0.40 = 20 and 150 × 0.10 = 15 errors. There are 35 errors among 200 forms, giving 35/200 × 100% = 17.5%. Taking the simple average of 40% and 10% gives 25%, but that wrongly weights the unequal batch sizes equally.

Question 12: Changing the empty share of a tank

Question 12 · Changing the empty share of a tank · hard

A tank is initially 20% empty. After 18 liters are removed, it is 35% empty. The tank’s capacity does not change, and no liquid is added. How many liters remain in the tank?

Choose an answer for question 12
Worked answer and explanation

Answer: C. 78 liters

Removing 18 liters increases the empty share by 35% − 20% = 15% of capacity. Capacity is therefore 18/0.15 = 120 liters. The tank is now 65% full, leaving 0.65 × 120 = 78 liters. Forty-two liters is the empty space after removal; 96 liters is the amount before removal.

Decide what to do next

  • Could not choose a setup? Repeat the matching worked method, then explain why each step fits the prompt.
  • Setup was right, calculation was wrong? Write the arithmetic in smaller steps and use the example’s check.
  • Solved it independently? Revisit two questions tomorrow and again later in the week before choosing a new lesson.

A remembered choice letter is different from a method you can reconstruct. Keep one correction in your error log and use it on your next attempt.